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0=-16x^2-30x+600
We move all terms to the left:
0-(-16x^2-30x+600)=0
We add all the numbers together, and all the variables
-(-16x^2-30x+600)=0
We get rid of parentheses
16x^2+30x-600=0
a = 16; b = 30; c = -600;
Δ = b2-4ac
Δ = 302-4·16·(-600)
Δ = 39300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{39300}=\sqrt{100*393}=\sqrt{100}*\sqrt{393}=10\sqrt{393}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-10\sqrt{393}}{2*16}=\frac{-30-10\sqrt{393}}{32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+10\sqrt{393}}{2*16}=\frac{-30+10\sqrt{393}}{32} $
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